at what height from the earth surface does the accelaration due to gravity decrease by 75 of its value at earth surface
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HEY MATE YOIR ANSWER IS AS FOLLOWS:--->
We know that gravity at any height is given as=>
g’ = g (1 - 2h/R) —[1]
Decrease by 1% implies that g’ = 99/100g
Substitute In 1,we get
99/100g = g (1 - 2h/R)
99/100 = 1 - 2h/R
2h/R = 1 - 99/100
2h/R = 1/100
h = R/200
h = 6400/200 (R = 6400KM)
Answer is :->>>
H = 32KM From surface of earth
REGARDS, BRAINLY EXPERT
We know that gravity at any height is given as=>
g’ = g (1 - 2h/R) —[1]
Decrease by 1% implies that g’ = 99/100g
Substitute In 1,we get
99/100g = g (1 - 2h/R)
99/100 = 1 - 2h/R
2h/R = 1 - 99/100
2h/R = 1/100
h = R/200
h = 6400/200 (R = 6400KM)
Answer is :->>>
H = 32KM From surface of earth
REGARDS, BRAINLY EXPERT
Answered by
1
We know that gravity at any height is given as=>
g’ = g (1 - 2h/R) —[1]
Decrease by 1% implies that g’ = 99/100g
Substitute In 1,we get
99/100g = g (1 - 2h/R)
99/100 = 1 - 2h/R
2h/R = 1 - 99/100
2h/R = 1/100
h = R/200
h = 6400/200 (R = 6400KM)
Answer is :->>>
H = 32KM From surface of earth
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