at what percent will a sum of rupees 64000 be compounded to 68921 in 3 years?
Answers
Answered by
104
The compound interest formula is as follows:
A = P (1 + r/n)ᵃᵇ
A = 68921
P = 64000
r = ?
a= 1
b= 3
68921 = 64000 ( 1 + r/1) ¹ˣ³
68921 = 64000 ( 1 + r)³
(1+r)³ = 68921/64000 = 1.076890625
(1+r)³ = 1.076890625...........find cube root of both
1+r = 1.025
r = 1.025 - 1
r = 0.025
r = 0.025 x 100% = 2.5%
Therefore the percent rate = 2.5%
A = P (1 + r/n)ᵃᵇ
Where:
A = The total sum accrued, sum + interest
P = the principal investment amount
r = the annual interest rate (decimal)
a = the number of times that interest is compounded per year
b= the number of years the money is invested or borrowed for
A = 68921
P = 64000
r = ?
a= 1
b= 3
68921 = 64000 ( 1 + r/1) ¹ˣ³
68921 = 64000 ( 1 + r)³
(1+r)³ = 68921/64000 = 1.076890625
(1+r)³ = 1.076890625...........find cube root of both
1+r = 1.025
r = 1.025 - 1
r = 0.025
r = 0.025 x 100% = 2.5%
Therefore the percent rate = 2.5%
vishalmodak:
sorry your answer is wrong
Answered by
226
Formula for finding Amount
A= P( 1+ R/100)^n
A= Amount in ₹
P= Principal in ₹
R= rate of interest in %
n= time period in years
Given:
A= ₹68921, P= ₹64000, n= years
A= P( 1+ R/100)^n
68921 = 64000 (1+ R/100)³
68921/64000 = (1+R/100)³
(41/40)³ = (1+R/100)³
[68921= 41³, 64000= 40³]
41/40 = (1+R/100)
41/40 - 1= R/100
(41-40)/40 = R/100
1/40 = R/100
40R= 100
R= 100/40= 10/4= 5/2= 2.5%
R= 2.5%
Rate percent = 2.5%
================================================================
Hope this will help you...
A= P( 1+ R/100)^n
A= Amount in ₹
P= Principal in ₹
R= rate of interest in %
n= time period in years
Given:
A= ₹68921, P= ₹64000, n= years
A= P( 1+ R/100)^n
68921 = 64000 (1+ R/100)³
68921/64000 = (1+R/100)³
(41/40)³ = (1+R/100)³
[68921= 41³, 64000= 40³]
41/40 = (1+R/100)
41/40 - 1= R/100
(41-40)/40 = R/100
1/40 = R/100
40R= 100
R= 100/40= 10/4= 5/2= 2.5%
R= 2.5%
Rate percent = 2.5%
================================================================
Hope this will help you...
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