At what point does the graph of equation 2x+3y=9 meet a line which is parallel to y -axis at a distance 4 units from the origin and on the right side of the y-axis
Answers
Answer:
(4,⅓)
Step-by-step explanation:
Given an equation of a line such that,
2x + 3y = 9
Also, statement is given for another line.
The another line is parallel to y axis at a distance of 4 units from the origin.
Therefore, clealry, we have,
Since it's parallel to y axis,
Therefore, the x coordinate will be fix throughout the line.
And, it's diatance from origin is 4 units.
Therefore, the eqn will be,
x = 4.
Now, substituting this value in eqn of first line,
Therefore, we will get,
=> 2(4) + 3y = 9
=> 8 + 3y = 9
=> 3y = 9 - 8
=> 3y = 1
=> y = ⅓
Therefore, point of intersection is (4,⅓).
Hence, the graph of the given line will meet the another line at the point (4,⅓).
Answer: (4,⅓)
Step-by-step explanation:
Given an equation of a line such that,
2x + 3y = 9
Also, statement is given for another line.
The another line is parallel to y axis at a distance of 4 units from the origin.
Therefore, clealry, we have,
Since it's parallel to y axis,
Therefore, the x coordinate will be fix throughout the line.
And, it's diatance from origin is 4 units.
Therefore, the eqn will be,
x = 4.
Now, substituting this value in eqn of first line,
Therefore, we will get,
=> 2(4) + 3y = 9
=> 8 + 3y = 9
=> 3y = 9 - 8
=> 3y = 1
=> y = ⅓
Therefore, point of intersection is (4,⅓).
Hence, the graph of the given line will meet the another line at the point (4,⅓).