at what rate of ci on a sum of rs 15625 at 4 percent for 3 years compounded anually.
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Let principal = $ P, rate = R % per annum and time = n years.
Then, the amount A is given by the formula
A = P (1 + R/100)n
Therefore, compound interest = (amount) - (principal).
1. Find the amount of $ 8000 for 3 years, compounded annually at 5% per annum. Also, find the compound interest.
Solution:
Here, P = $ 8000, R = 5 % per annum and n = 3 years.
Using the formula A = $ P(1 + R/ 100)n
amount after 3 years = $ {8000 × (1 + 5/100)3}
= $ (8000 × 21/20 × 21/20 × 21/20)
= $ 9261.
Thus, amount after 3 years = $ 9261.
And, compound interest = $ (9261 - 8000)
Therefore, compound interest = $ 1261.
2. Find the compound interest on $ 6400 for 2 years, compounded annually at 71/2 % per annum.
Solution:
Here, P = $ 6400, R % p. a. and n = 2 years.
Using the formula A = P (1 + R/100)n
Amount after 2 years = [6400 × {1 + 15/(2 × 100)}2]
= $ (6400 × 43/40 × 43/40)
=$ 7396.
Thus, amount = $ 7396
and compound interest = $ (7396 - 6400)
Therefore, compound interest = $ 996.
When interest is compounded annually but time is a fraction
For example suppose time is 23/5 years then,
Amount = P × (1 + R/100)2 × [1 + (3/5 × R)/100]
1. Find the compound interest on $ 31250 at 8 % per annum for 2 years. Solution Amount after 23/4 years
Solution:
Amount after 23/4 years
= $ [31250 × (1 + 8/100)2 × (1 + (3/4 × 8)/100)]
= ${31250 × (27/25)2 × (53/50)}
= $ (31250 × 27/25 × 27/25 × 53/50)
= $ 38637.
Therefore, Amount = $ 38637,
Hence, compound interest = $ (38637 - 31250) = $ 7387.
hope it will help you.
please mark it as brainliest.
Then, the amount A is given by the formula
A = P (1 + R/100)n
Therefore, compound interest = (amount) - (principal).
1. Find the amount of $ 8000 for 3 years, compounded annually at 5% per annum. Also, find the compound interest.
Solution:
Here, P = $ 8000, R = 5 % per annum and n = 3 years.
Using the formula A = $ P(1 + R/ 100)n
amount after 3 years = $ {8000 × (1 + 5/100)3}
= $ (8000 × 21/20 × 21/20 × 21/20)
= $ 9261.
Thus, amount after 3 years = $ 9261.
And, compound interest = $ (9261 - 8000)
Therefore, compound interest = $ 1261.
2. Find the compound interest on $ 6400 for 2 years, compounded annually at 71/2 % per annum.
Solution:
Here, P = $ 6400, R % p. a. and n = 2 years.
Using the formula A = P (1 + R/100)n
Amount after 2 years = [6400 × {1 + 15/(2 × 100)}2]
= $ (6400 × 43/40 × 43/40)
=$ 7396.
Thus, amount = $ 7396
and compound interest = $ (7396 - 6400)
Therefore, compound interest = $ 996.
When interest is compounded annually but time is a fraction
For example suppose time is 23/5 years then,
Amount = P × (1 + R/100)2 × [1 + (3/5 × R)/100]
1. Find the compound interest on $ 31250 at 8 % per annum for 2 years. Solution Amount after 23/4 years
Solution:
Amount after 23/4 years
= $ [31250 × (1 + 8/100)2 × (1 + (3/4 × 8)/100)]
= ${31250 × (27/25)2 × (53/50)}
= $ (31250 × 27/25 × 27/25 × 53/50)
= $ 38637.
Therefore, Amount = $ 38637,
Hence, compound interest = $ (38637 - 31250) = $ 7387.
hope it will help you.
please mark it as brainliest.
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ci=15625X4 X3/100
Ci=1875 Rup.
Thank U
Ci=1875 Rup.
Thank U
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