Question

at what rate percent of CI will rupees 4000 amount to rupees 5324 in 3 years

Answer 1

Amount is ₹5324

Principal is ₹4000

so,
5324= 4000(1+r/100)^3
=5324/4000=[(100+r)/100]^3
=11/10*100=100+r
=r=110-100
=r=10

hope it helps you

Answer 2

Answer:

The rate percent is 10%.

Step-by-step explanation:

In context to the question asked,

We have to find the rate percent,

As per data given in the question,

Principal ( P ) = Rs. 4,000

Amount ( A ) = Rs. 5324

Time ( T ) = 3 years

As we know that,

$A= P[1+\frac{R}{100}]^n$

Substitute the given values in the formula,

$=> 5324= 4000[1+\frac{R}{100}]^3$

Simplifying it further, we get

$=> \frac{5324}{4000} = [1+\frac{R}{100}]^3$

$=> \frac{11}{10} = [\frac{100+R}{100}]^3$

$=> \frac{11}{10}\times 100 = 100+R$

$=> 110 = 100+R$

$=> 110 -100= R$

$=> 10 = R$

Move variable to the left side,

$=> R = 10$

Hence, the required rate percent is 10%.