Question

At what rate percent per a nnumn will rs 9000 amount to rs 10240 in 2 years , compounded annually

Answer 1

Answer:

The answer is 3.59 percent of rate

A = P(1+r/n)^nt

10240= 900(1+r/2)^2×2

which gives r=(166.1)^1/4

r= 3.59 %

Answer 2

$\mathbb{ANSWER}$

$\rule{300}{1}$

Given Principle $P=9000$$Amount(A)=10240$$Time(n)=2years$

$\rule{300}{1}$

Now,

$Amount=(A)=P$${\left(1+\dfrac{r}{100}^{n}\right)}$

$\rightarrow$$10240=9000$${\left(1+\dfrac{r}{100}^{2}\right)}$

$\rightarrow$${\left(1+\dfrac{r}{100}^{2}\right)}$$=$$\dfrac{10240}{9000}$

$\rightarrow$${\left(1+\dfrac{r}{100}^{2}\right)}$$=$${\left(\dfrac{32}{30}^{2}\right)}$

$\rightarrow$$1+$$\dfrac{r}{100}$$=$$\dfrac{32}{30}$$-1$

$\rightarrow$$\dfrac{r}{100}$$=$$\dfrac{32}{30}$$-1$

$\rightarrow$$\dfrac{r}{100}$$=$$\dfrac{2}{30}$

$\rightarrow$$r=$$\dfrac{{2}\times{100}}{30}$$=$

$\rightarrow\dfrac{20}{3}$

$\rule{300}{1}$

Hence, required rate of interest is $\dfrac{20}{3}$

$\rule{300}{1}$