At what rate percent will a sum of Rs 64000 be compounded to Rs 68921 in 3 years?
Answers
Answered by
146
Heya friend,
Given that
P = ₹64,000
A = ₹68,921
T = 3 years
Solution
A = P(1+R/100)^n
=> 68,921 = 64,000(100+R/100)^3
=> 3√68,921/64,000 = 100+R/100
=> 41/40 = 100+R/100
=> 41 × 100 = 40(100+R)
=> 4,100 = 4,000+ 40R
=> 4,100 - 4,000 = 40R
=> 100 = 40R
=> R = 100/40
=> R = 5/2 % p.a. or 2.5% p.a.
Thanks
With regards@
Tanisha
Given that
P = ₹64,000
A = ₹68,921
T = 3 years
Solution
A = P(1+R/100)^n
=> 68,921 = 64,000(100+R/100)^3
=> 3√68,921/64,000 = 100+R/100
=> 41/40 = 100+R/100
=> 41 × 100 = 40(100+R)
=> 4,100 = 4,000+ 40R
=> 4,100 - 4,000 = 40R
=> 100 = 40R
=> R = 100/40
=> R = 5/2 % p.a. or 2.5% p.a.
Thanks
With regards@
Tanisha
Answered by
80
Answer:
2.5 % is the rate of interest
Step-by-step explanation:
Here ( P ) principal = ₹64000
( A ) Amount = ₹68921
( n ) Time period = 3 yrs
Let R be the rate of interest
We know that amount = P ( 1 + R/100 )
And by using this formula,we have the answer as 2.5 %
(please refer the attachment)
Hope it helps ya... ✌✌✌✌✌
Attachments:
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