Question

At what temperature (in k)would the rms speed of a molucule of hydrogen gas be 2170 m/s?

Answer 1

Answer:

53degree Celsius

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Answer 2

Answer:

Explanation:

Given r.m.s velocity of hydrogen is 2170

We know that r.m.s velocity is (3RT/M)^1/2= 2170. mass of hydrogen is 1 and R value is 8.314 ×10^7ergs

T=(2170);2×1/8.314×10^7

T=0.05339272