At what temperature is the kinetic energy of gas
molecule double that of its value at 27°C
(1) 54°C
(2) 300K
(3) 327°C
(4) 108°C
Answers
Answered by
1
Answer:
600K
units, 27 °C= 300 K. If we double the temperature, K.E. gets doubled. So 600K or 327°C is required temperature.
Answered by
6
Answer:
hey dear
at 27 deg celcius
in kinetic energy
= 1 Kelvin = 273deg
273 + 27 deg
=300 kelvin
3 ✅✅
hope it's helpful for you.
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