Question

At what temperature is the kinetic energy of gas
molecule double that of its value at 27°C
(1) 54°C
(2) 300K
(3) 327°C
(4) 108°C​

Answer 1

Answer:

600K

units, 27 °C= 300 K. If we double the temperature, K.E. gets doubled. So 600K or 327°C is required temperature.

Answer 2

Answer:

hey dear

at 27 deg celcius

in kinetic energy

= 1 Kelvin = 273deg

273 + 27 deg

=300 kelvin

3 ✅✅

hope it's helpful for you.

mark my answer as brainlist.