Question

At what temperature, the average speed of gas
molecules will be double that at 27°C ?​

Answer 1

Answer:

ANSWER:

We know,

Average speed,

V=√(8R*T/πM).

At 27 C.

V1= √(8R*27/πM).

Let V2 be the speed which is double of V1 so,

V1/V2=√(8R*T/πM)/√(8R*27/πM).

1/2=√27/√T2.

Squaring on both the sides we get,

T2=27*4.

T2=108 C.