Physics, asked by FlyingNinja2004, 11 months ago

Find the acceleration of the blocks and tension in the string.​

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Answered by lovish95
0

hey you did not tell anything about 1kg block is it fixed or movable ...

if fixed then here we go.....the string ais massless so tension in string is same and also bolck have same accelertion but opposite direction.....

force on 3kg block-

3g-T=3a

on 2kg block -

T-2g=2a

adding both equation and after solving it we got a=2m/s².

put value of a in any equation you got the tension 24N..

if this helped you pls mark it as brainliest....

Answered by Rockysingh07
0

or A:

F−T=10a1⇒60−T1=10a1F−T=10a1⇒60−T1=10a1 -------(1)

For B:

T1−T2=ma2⇒60−10a1−T2=10a2T1−T2=ma2⇒60−10a1−T2=10a2 (from (1) )

For C:

T2=ma3⇒6=a1+a2+a3T2=ma3⇒6=a1+a2+a3 (from last eqn. and further simplifying)

But, this is certainly not any closer to the 1st part which asks for acceleration of 3 Blocks. I don't have a single idea how to deal here with 3 acceleration variables (a1,a2a1,a2 and a3a3) and 3 tension Variables (T1,T2T1,T2 and T3T3) and use those here. I'm missing something here and I don't know how to proceed with the equations further.

For the second part, I can make a wild guess that tensions should be equal everywhere in the string, but as explained earlier due to the problem with equations I don't have enough idea to prove it as I've explained earlier that I had problems with the equation.

Note: My assumptions about the second part that tensions should be equal everywhere can be wrong as it's just a mere guess, I've not proved it.

Any help/hint is appreciated,

Best Regards :)

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