Question

At what temperature the pressure of p of a certain mass of a gas at 47degrees will be one fourth keeping the volume constant

Answer 1

As we know that P V = n R T

as P is constant......so,

V is directly proportional to T.

After doubling new volume will be 2V

let the new temperature be T'

As PV = nRT

or, T = PV/nR.............1

P(2V) = nRT'..............2

so, T' = 2PV/nR

so, T' = 2T .........{from 1}

As T = 37℃ = 273+37 = 310 K

so, T' = 2×310 = 620 K

= 620-273

= 347℃ or 620 K.

Answer 2

Explanation:

T1= 273+47=320 K.

P1=p;

P2=(1/4)p=0.25p

T2 is unknown.

we know,

pressure is directly proportional to temperature.

then,

T2:T1=P2:P1.

T2:320=0.25p:p

T2=0.25*320

=80K

80K is (80-273)=-193°C.