At what temperature the resistance of a thermometer will be 12% more of its resistance at 0°C
(given temperature coefficient of resistance is 2.5 × 10-3 °C-1?
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Given :
- T⁰ = 0
- Resistance at T⁰ = R⁰
- Resistance at T ⁰C = R = R⁰ + 0.12 R⁰ = 1.12 R⁰
- Temperature coefficient of resistance = α = 2.5 x 10-³ /C
Solution :
As per the formula ,
R = R⁰ ( 1 + αΔT )
➜ 1.12 R⁰= R⁰ ( 1 +αΔT )
➜ 1.12 = 1 + αΔT
➜ 1.12 - 1 = αΔT
➜ ΔT = 0.12 x 1000 / 2.5
➜ ΔT = 48 ⁰ C
Now ,
➜ ΔT = T - T⁰ = 48
Hence ,
➜ T - T⁰ = 48
➜ T - 0 = 48
➜ T = 48 ⁰ C
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