Question

At what temperature the sample of neon gas would be heated to double its pressure if the initial volume of fas is reduced by 15% at 15 degree celcius

Answer 1

Answer:

318.6°C

Explanation:

By ideal gas equation,

P1.V1/T1 = P2.V2/T2

T1 = 273 + 75 = 348K

P2 = 2P1

Initial volume = V1

V2 = V1 - 15V1/100 = 0.85V1

T2 = ?

P1.V1/348 = 2P1 × 0.85V1/T2

1/348 = 2 × 0.85/T2

T2 = 348 × 1/7 = 591.6K

In degrees, 591.6 - 273 = 318.6°C

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Answer 2

318.6degree celsius..

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