Question

At what temperature the volume of "V" of a certain mass of gas at 37degree centigrade will be doubled, keeping pressure constant? ​

Answer 1

Answer:

V1=V

therefore,V2=2V

T1=37°C=310K

T2=?

therefore,V1/T1=V2/T2

or,V/310=2V/T2

or,T2=2V×(310/V)

or,T2=620K

the volume of the gas will double at 620K

Explanation:

comment me if you do not understand

Answer 2

Answer: Given that,

V2=2V, V1=V.,T1=310 T2=?

Explanation:

V ∝ n at constant pressure

V2/V1 = T2/T1

2V/V = T2/310

T2=620 K

Convert kelvin to celcius then we will get,

T2= 347 C

Hope it helps you