Question

At what temperature volume of
definite amount of gas measured at
27°C will be triple while pressure
remains same?​

Answer 1

Answer:

327 degree C

Explanation:

Using gas equation, we have

(P1*V1) /T1=(P2*V2) /T2 where P=Pressure, V=Volume and T=Absolute temperature of the gas.

Given, P1=P2=P(say) (Since pressure is constant)

V1=V(say), where V is the initial volume of the gas.

Therefore, V2=2V since final volume is double the initial volume.

T1=(27+273)K=300K

T2=?

Substituting the values obtained,in the gas equation, we have

P*V/300=P*2V/T2

Solving, we get T2=final temperature of the gas=600K or (600–273)degree C or 327 degrees C.

Hope its helpful

Answer 2

Answer:

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