Question

at what temperature will a given mass of a gas occupies a volume of 200 l if it occupy a volume of 260 l at a temperature of 30 degree celsius pressure remaining constant

Answer 1

Answer:

Hope this helps.......

Answer 2

Answer:

initial temperature would be 233 K.

Explanation:

Given :

• Initial volume (V1) = 200 L
• Final volume (V2) = 260 L
• Final temperature (T2) = 30°C

To find ;

• Initial temperature

Solution :

Let's change the temperature in Kelvin first,

T2 = 30°C

→ T2 = 30 + 273

→ T2 = 303 K

Using Charle's law,

V1/T1 = V2/T2

→ 200/T1 = 260/303

→ T1 = (303 × 200)/260

→ T1 = 233 K

Hence, initial temperature would be 233 K.