Question

At what temperature will O2, have the same density
as N2, at 0°C, assuming pressure remains
constant?​

Answer 1

Hello Dear,

◆ Answer -

T2 = 39 ℃

◆ Explaination -

Let N2 be 1 and O2 be 2.

Density of N2 at 0 ℃ is given by -

d1 = W1 / V1

d1 = M1 × n1 / V1

d1 = M1 × P / RT1 ...(PV = nRT)

Density of O2 a temp T2 is given by -

d2 = W2 / V2

d2 = M2 × n2 / V2

d2 = M2 × P / RT2 ...(PV = nRT)

Given that,

d1 = d2

M1 × P / RT1 = M2 × P / RT2

T2 = M2 × T1 / M1

Substitute values,

T2 = 32 × 273 / 28

T2 = 312 K

T2 = 312-273 ℃

T2 = 39 ℃

Hence at 39 ℃, O2 will have same density as that of N2 at 0 ℃.

Thanks dear...

Answer 2

Answer:

39degree celcius

Explanation:

first take N2

d1=M1P/RT1..........(PV=RT)

Now take O2

d2=M2P/RT2..........(PV=RT)

Given,

N2 temp T1=0°c=273k

we know that

molar mass of N2, M1=28

O2, M2=32

d1=d2

28 = 32

273. T2

T2= 32*273

28

= 312k

T2 = 39°c

thank you

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