at what temperature will the reading on the degree fahrenheit scale be double then that on degree Celsius scale
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I would represent it as such:
Basic conversion formula: F = 9/5C + 32
Our problem: 2C = F
Substitute F in the first formula with 2C from the second, which gives you:
2C = 9/5C + 32
Subtract 9/5C from both sides, which gives:
2C - 9/5C = 32
Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32
Multiply 5 to each side, which leaves C = 160
So, 160 degrees Celsius will equal 320 degrees Fahrenheit.
Basic conversion formula: F = 9/5C + 32
Our problem: 2C = F
Substitute F in the first formula with 2C from the second, which gives you:
2C = 9/5C + 32
Subtract 9/5C from both sides, which gives:
2C - 9/5C = 32
Simplify the left side (2C = 10/5C): 10/5C - 9/5C = 32, which equals 1/5C = 32
Multiply 5 to each side, which leaves C = 160
So, 160 degrees Celsius will equal 320 degrees Fahrenheit.
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