Question

at what temperature will the speed of sound in air be 3 times its value at 0

C ?

Answer 1

speed of sound is directly proportional to the √T

V1/V2 = √T1/√T2

V/3V = √273/√T2 (0°C = 273K)

squaring both the sides

T2 = 9 X 273 = 2457K = 2184°C

Answer 2

Dear Student,

◆ Answer -

T' = 2184 ℃

● Explanation -

# Given -

T = 0 ℃ = 273 K

v = 340 m/s

v' = 3v

# Solution -

Velocity of sound at T ℃ is given by -

v'/v = √(T'/T)

T'/T = (v'/v)^2

T' = T.(v'/v)^2

T' = 273 × (3v/v)^2

T' = 273 × 9

T' = 2457 K

T' = 2184 ℃

Hence, speed of sound will triple at 2184 ℃.

Thank you...