Question

At what temperature would the.
resistance of copper be double its resistance at
0°C? a for copper is 10-3PC.​

Answer 1

Answer:

R=2Ro

α=3.9×10−3C−1

ΔT=T−To

Ro and To are resistance and temperature at 0∘C

R and T are resistance and temperature at T∘C

R=Ro(1+αΔT)

Substituting the given information,

2Ro=Ro(1+αΔT)

2=1+αΔT

1=αΔT

1=3.9×10−3ΔT

ΔT=256.41∘C

T−To=T−0=T=256.41∘C

Hence the correct option is (A).

Explanation:

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