Question

@1. The number of water of
erystallisation present in blue
vitrol ( CuSO4.5H2O).​

Answer 1

The molecular weight of Water : $\large\rm { H_{2} O = 2(1) + 16 = 18 \ g/mol }$

The molecular weight of copper sulphate pentahydrate $\large\rm { CuSO_{4} \cdot 5H_{2} O = 64+32+4(16)+5(18) = 250 \ g/mol}$

The percentage of water crystallization :

$\large\rm { \frac {5×18}{250} × 100 = 36 }$

$\large\rm { \therefore 36 \% }$ is the required answer.

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Answer 2

Answer:

Blue vitriol is copper sulphate penta hydrate CuSO4⋅5H2O

The molecular weight of CuSO4⋅5H2O is:

63.5+32+4(16)+5(18)=249.5 g/mol

The percentage of water of crystallisation of a sample of blue vitrol → $\frac{5 \times 18}{250} \times 100 = 36.07\%$