@3+6+9+---+300@
@find the sum@
#it is from ch arithmetic progression#
@plz with method find it..@
Answers
Answered by
1
first term a= 3.... common difference d= 3
nth term = a+ (n-1)d
300= 3+ (n-1)3
n= 100
number of terms = 100
so sum = n/2{first term + last term}
= 100/2(3+300)= 50*303= 15150
nth term = a+ (n-1)d
300= 3+ (n-1)3
n= 100
number of terms = 100
so sum = n/2{first term + last term}
= 100/2(3+300)= 50*303= 15150
niharika44:
in this how to find no. of terms but
u said it is 100 where it is written
now i corrected it check it again
if u understand it tell me
oh thx so much actually I was confused
I understood
ur welcome but y d way no need to say thanks...
okk
hmm
Answered by
2
An = a+(n-1)d
300= 3+(n-1)3
(300-3)3= n-1
99+1= n
n=100
Sn = n/2(a+l) =100/2(3+300)=50×303=15150
300= 3+(n-1)3
(300-3)3= n-1
99+1= n
n=100
Sn = n/2(a+l) =100/2(3+300)=50×303=15150
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