athe perimeter of a triangle is 14a square +20a + 13. two of its side are 3a square +5a +1 and a square +10a-6. find
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As we know that the perimeter of a triangle is the sum of all the sides.
Suppose that the third side of the triangle is X then,
According to the given data in the question-
14a2+20a+13=3a2+5a+1+a2+10a−6+X
14a2+20a+13=4a2+15a−5+X
X=14a2+20a+13−(4a2+15a−5)
X=14a2+20a+13−4a2−15a+5
X=10a2+5a+18
Hence, the third side will be 10a2+5a+18.
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