AThus 34
= 4 [(x-7)+01-6)) = 4QB2
AThus 3AQ = 2QB. This means that Q(x, y) satisfies (1).
Hence, the required equation of locus is 5(x + y) - 34x + 120y +29=0.
5. Problem: A (2, 3) and B(-3, 4) are two given points. Find the equation of locus of P 30
the area of the triangle PAB is 8.5)
Solution: Let P(x,y) be a point on the locus.
The geometric condition to be satisfied by Pis that,
area of A PAB = 8.5
i.e., x(3 - 4)+24 - y) – 3(y - 3) = 8.5
i.e., |- x +8 - 2y - 3y + 91 = 17
Answers
Answered by
1
Answer:
100-5y
Step-by-step explanation:
91+8+1-2y-5y
100-5y
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