Question

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Can You Solve It;

The coach of a cricket team buys 7 bats and 6 balls for ₹ 3800. Later, she buys 3 bats and 5 balls for ₹ 1750. Find the cost of each bat and each ball.
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Answer 1

Step-by-step explanation:

Let the cost of one Bat be x

and the cost of one ball be y

Then According to Question

7x+6y=3800 ---(i)

3x+5y=1750 ---(ii)

multiplying (i) by 3 and (ii) by 7 we get

21x+18y=11400 (iii)

21x+35y=12250 (iv)

subtracting (iv) from (iii) we get

−17y=−850

⇒y=50

putting y=50 in (i)

7x+6y=3800

⇒7x+6×50=3800

⇒7x=3800−300

⇒x=500

Therefore the cost of each bat is Rs 500

and the cost of each ball is Rs 50

I hope you are satisfied from my answer

Answer 2

Answer:

• The cost of each bat and each ball are ₹500 and ₹50 respectively.

Step-by-step explanation:

Given,

• The coach of a cricket team buys 7 bats and 6 balls for ₹ 3800.
• Later, she buys 3 bats and 5 balls for ₹ 1750.

To Find,

• Thee cost of each bat and each ball.

Solution,

Let's,

• The cost of each bat = x

And,

• The cost of each ball = y

According to Question,

By the 1st Situation,

• 7x + 6y = 3800 •••[1]

By the 2nd Situation,

• 3x + 5y = 1750 •••[2]

We have,

• 7x + 6y = 3800 •••[1]
• 3x + 5y = 1750 •••[2]

Finding the value of x in terms of y by Eq (2),

• ➤ 3x + 5y = 1750 •••[2]
• ➤ x = (1750 - 5y)/3 •••[3]

Substituting this value of x in Eq (1),

• ➤ 7x + 6y = 3800 •••[1]
• ➤ 7[(1750 - 5y)/3] + 6y = 3800

Multiplying 3 by Both sides,

• ➤ 3{7[(1750 - 5y)/3] + 6y} = 3(3800)
• ➤ 7(1750 - 5y) + 18y = 11400
• ➤ 12250 - 35y + 18y = 11400
• ➤ -17y = -850
• ➤ y = 50

Substituting this value of y in Eq (3),

• ➤ x = (1750 - 5y)/3 •••[3]
• ➤ x = (1750 - 250)/3
• ➤ x = 500

Therefore, x = 500 and y = 50

The cost of each bat = x

• The cost of each bat = ₹ 500

The cost of each ball = y

• The cost of each ball = ₹ 50

Required Answer,

• The cost of each bat and each ball are ₹500 and ₹50 respectively.