Question

Atom of an element contains five electrons in its valence shell. This element is major component of air. It exists as a diatomic molecule. (i) Identify the element. (ii) show the bond formed between two atoms of this element. (iii) write the nature of the bond between the two atoms.?

Answer 1

it is nitrogen as the atomic no. of nitrogen is 7

the electronic configuration is 2,5 .

N---N

TRIPLE BOND

Answer 2

Explanation:

The given atom has 5 valence electron in valence shell and major component of the air.Also exist as diatomic  molecule.

i) The element is Nitrogen atom which have 5 valence electrons in its valence shell with atomic number of 7.

$[N]=1s^22s^22p^3$

ii) In order to obtain the noble gas configuration nitrogen atom shares its 3 valence electrons with another nitrogen atom. And due to sharing of three electrons by both nitrogen atoms triple bond forms between both the atoms.

iii)Triple bond between thr two nitrogen atom is a strong bond..

$N\equiv N$