Question

atomic mass of boron is 10.81.it has two isotopes with 80%and 20% abundance the atomic mass of the 80% isotope is 11.01 then find the atomic mass of other isotope

Answer 1

10.81 = 11.01 * 80 + x *20 ÷ 100



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Answer 2

The atomic mass of isotope 2 of boron is 10.01 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$   .....(1)

Let the mass of isotope 2 be 'x'

• For isotope 1:

Mass of isotope 1 = 11.01 amu

Percentage abundance of isotope 1 = 80 %

Fractional abundance of isotope 1 = 0.80

• For isotope 2:

Mass of isotope 2 = x

Percentage abundance of isotope 2 = 20 %

Fractional abundance of isotope 2 = 0.20

Average atomic mass of boron = 10.81 amu

Putting values in equation 1, we get:

$10.81=[(11.01\times 0.80)+(x\times 0.20)]\\\\x=10.01amu$

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