Question

ATOMIC MASS OF GOLD (AU) IS 197U. HOW MANY MOLES OF GOLD ARE PRESENT IN AN ORNAMENT CONTAINING 88.65 GRAM OF GRAM.

Answer 1

 in 197g of gold = 1 mole so, 88.65 grams = (1/197)x 88.65 = 0.45 mol

Answer 2

There are 0.45 moles in 88.65 grams of gold.

Explanation:

We have

Atomic mass of gold, M = 197 u

It is required to find the number of moles of gold that are present in an ornament containing 88.65 grams of gold. Let there are n moles. Number of moles is given by :

$n=\dfrac{m}{M}$

m is given mass

$n=\dfrac{88.65}{197}\\\\n=0.45$

So, there are 0.45 moles in 88.65 grams of gold.

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Mole concept

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