Atomic radius of li is 1.23angstrom and ionic radus of li+ is 0?76 angstrom.the fraction the volume occupied by 2s electron in li is
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Given:
Radius of Lithium Li = 1.23 Angstrom
Ionic radius of Li+= 0.76 Angstrom
Solution:
Volume of lithium Li = 4/3 pi r^3 = 4/3 * 22/7 * 1.23^3 = 7.79 Angstrom^3
Volume of lithium L+i = 4/3 pi r^3 = 4/3 * 22/7 * 0.76^3 = 1.84 Angstrom^3
Configuration of Li is 1s2 2s1
Configuration of Li+ is 1s2
Volume of electron in 2s shell will be 7.79 – 1.84 = 5.95 Angstrom
So, percentage of volume occupied by single valence electron will be 5.95/7.79 * 100 = 76.4%
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Answer:
76.4
Explanation:
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