Atoms present in 0.1 mole of so2
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Heya user ,
Here is your answer !!
No. of atoms present in 1 mole of any substance = 6.022 * 10^23
Therefore , no. of atoms present in 1 mole of SO2 = 6.022 * 10^23 atoms .
So, no. of atoms present in 0.1 mole of SO2 = 6.022 * 10^22 atoms .
Hope it helps !!
Here is your answer !!
No. of atoms present in 1 mole of any substance = 6.022 * 10^23
Therefore , no. of atoms present in 1 mole of SO2 = 6.022 * 10^23 atoms .
So, no. of atoms present in 0.1 mole of SO2 = 6.022 * 10^22 atoms .
Hope it helps !!
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