atoms present in 4.25g of NH3
The number
of
is approx:
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0
Answer:
No. of Oxygen atoms in 8g of Ozone will be
4) 6.02×10²³/6
And atoms present in 4.25 g of NH3 is approx : 1.505 × 10²³ will be no. of molecules
So no. of atoms will be 6.02 × 10²³
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