Math, asked by bhavnatirkey, 7 months ago

the sum of deviation of a certain number of observation measured from 4 is 72 and the sum of observation of the sane value from 7 is -3 . find the number of observation and their mean. ​

Answers

Answered by MaheswariS
10

\textbf{Given:}

\text{Sum of deviation of observations from 4 is 72}

\text{Sum of deviation of observations from 7 is -3}

\textbf{To find:}

\text{Number of observations and mean}

\textbf{Solution:}

\text{Let n be the number of observations}

\text{As per given data,}

(x_1-4)+(x_2-4)+......+(x_n-4)=72

(x_1+x_2+.....+x_n)-4\,n=72

(x_1+x_2+.....+x_n)=72+4\,n

\Sigma\,x_i=72+4\,n ........(1)

\text{Also,}

(x_1-7)+(x_2-7)+......+(x_n-7)=-3

(x_1+x_2+.....+x_n)-7\,n=-3

(x_1+x_2+.....+x_n)=7\,n-3

\Sigma\,x_i=7\,n-3 ........(2)

\text{From (1) and (2), we get}

72+4\,n=7\,n-3

72+3=7\,n-4\,n

75=3\,n

\n=\dfrac{75}{3}

\implies\boxed{\bf\,n=25}

\text{Now,}

\text{Mean}=\dfrac{\Sigma\,x_i}{n}

\text{Mean}=\dfrac{7\,n-3}{n}

\text{Mean}=\dfrac{7(25)-3}{25}

\text{Mean}=\dfrac{175-3}{25}

\text{Mean}=\dfrac{172}{25}

\implies\boxed{\textbf{Mean}=\bf\,6.88}

\textbf{Answer:}

\textbf{Number of observations is 25}

\textbf{and mean 6.88}

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