Question

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Answer 1

Answer:

given 4 men can do as much work in 7 days i.e.,

7*4 men=  1work

=>1 man=1/28 work.This is the work done by one man in one day.

Similarly 6 women take the same time i.e., 7 days

=>6*7 women = 1 work

=>1 women= 1/42 work.This is the work done by 1 woman in 1 day

number of days required to finish the work by 8 men and 9 women working together is as follows

let no.of days taken to complete work be 'x'

x(8(1/28)+9(1/42))=1

On solving this we get x= 2

Hence 2 days were required to complete the work with the help of 8 men and 6 women.

Step-by-step explanation: