Attached earlobes is a recessive character present in 9 individuals in a population size of 100 individuals. Number of heterozygous in this population is
Answers
no of heterozygous in the population will be 42
here given q^2=9/100
q=.3
therefore p=.7
so frequency of heterozygous will be 2pq=2×.7×.3=.42
therefore no of heterozygous in the population will be .42×100=42
Answer:
Explanation:
Population Size = 100 (Given)
Recessive character presence = 9 individuals (Given)
As per Hardey Weinsberg equation -
p²+q² = 1
where, p² represents the frequency of the homozygous genotype AA, and q² represents the frequency of the homozygous genotype aa,
Thus,
the frequency of attached earlobes q² = 0.09 = q = 0.03
Frequency of the unattached earlobe ( dominant ) = 1 - 0.03 = 0.97
Percentage of population that are heterozygous for the earlobe allele -
2pq or 0.05 (where 2pq represents the overall frequency of the heterozygous genotype)
Therefore, the number of heterozygous in this population is 0.05