Biology, asked by smbehera2001, 1 year ago

Attached earlobes is a recessive character present in 9 individuals in a population size of 100 individuals. Number of heterozygous in this population is

Answers

Answered by huzurali453
42

no of heterozygous in the population will be 42

here given q^2=9/100

q=.3

therefore p=.7

so frequency of heterozygous will be 2pq=2×.7×.3=.42

therefore no of heterozygous in the population will be .42×100=42


smbehera2001: Thanks man ✌️
huzurali453: wc
Answered by Anonymous
6

Answer:

Explanation:

Population Size = 100 (Given)

Recessive character presence = 9 individuals (Given)

As per Hardey Weinsberg equation -

p²+q² = 1

where, p² represents the frequency of the homozygous genotype AA, and q² represents the frequency of the homozygous genotype aa,

Thus,

the frequency of attached earlobes q² = 0.09 = q = 0.03

Frequency of the unattached earlobe ( dominant ) = 1 - 0.03 = 0.97

Percentage of population that are heterozygous for the earlobe allele -

2pq or 0.05 (where 2pq represents the overall frequency of the heterozygous genotype)

Therefore, the number of heterozygous in this population is 0.05

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