Question

Attached is d question........

Answer 1

The answer is square and pyramid

Answer 2

Given that,

The diagonal BD divides the AC in AO : OC with 2 : 1

↪ To prove : AB = 2C

Proof :

In Δ AOC and Δ DOC

➡ AOB = COD

➡ OBA = ODC (Because DC is parallel to AB, and DB is transversal. So, these are alternates)

Therefore,

↪ Δ AOB is same as Δ COD (By AA similarity)

Δ AOB is same as Δ COD (By AA similarity)Now, AO/OC = AB/DC (Because in similar triangles sides are proportional)

➡ 2/1 = AB/DC (Given that AO : OC = 2 : 1)

So,

➡ AB = 2CD

Hence proved.

Step-by-step explanation:

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