Question

❤Attention Needed!! ❤



#sumedhian ❤❤​

Answer 1

Answer:

2.75l

Explanation:

using combined gas equation

P1V1/T1=P2V2/T2

p1 at stp =1atm

T1=273k

v1=?

p2convert to atm

1atm =760mmhg

380mmHg=1/2atm=0.5atm

T2=273c

convert to kelvin

k=c+273

273+273=546k

now by equation

1×v1/273=0.5×11/546

v1=0.5×11×273/546

v1=2.75l

u need 2.75l of O2 to burn 11 l of C2H4

Answer 2

Answer:

Fan of sumellika...

Explanation:

Sorry don't know the answer..