Math, asked by kambojshilpa73, 1 year ago

Atul earned 3,60,000 in the year 2010 and
3,88,800 in the year 2011.
(a) Find the percentage increase in his
annual income in the year 2011.
(b) If Atul's income in the year 2010 was
10% less than that in the previous year,
what was his annual income in the year
2009?​

Answers

Answered by anandsudhansh
7

Answer:

a)

percentage increase in income =8%

(b) 3,24,000

Explanation:

(a) 3,88,800 -3,60,000 =28,800

so, increase percentage =28,800×100/3,60,000

=8%

(b) 10% of income in 2010 =

10 × 3,60,000/100 =36,000

then his income in 2009 was = 3,24,000

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