Math, asked by my0554218, 10 months ago

Atwo+digit+number+is+4+times+the+sum+of+its+digits+if+18+is+added+to+the+number+the+digits+are+reversed+find+the+no:

Answers

Answered by Anonymous
3

Let unit place is x and tenth place is y so

Let unit place is x and tenth place is y soCondition 1

Let unit place is x and tenth place is y soCondition 1x +y = 12

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversed

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -18

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -18

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =18

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =189y- 9(12–y)= 18

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =189y- 9(12–y)= 189y-108+9y=18

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =189y- 9(12–y)= 189y-108+9y=1818y= 18+108

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =189y- 9(12–y)= 189y-108+9y=1818y= 18+108y = 126/18

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =189y- 9(12–y)= 189y-108+9y=1818y= 18+108y = 126/18y= 7

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =189y- 9(12–y)= 189y-108+9y=1818y= 18+108y = 126/18y= 7So x = 12–7 =5

Let unit place is x and tenth place is y soCondition 1x +y = 12Condition 2 if digit reversedy +10x = x + 10y -18y + 10x -x - 10y= -189x -9y = -189y -9x =189y- 9(12–y)= 189y-108+9y=1818y= 18+108y = 126/18y= 7So x = 12–7 =5Original number = 10x +y = 10x5+7= 57

Answered by rishu6845
3

Answer:

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