Physics, asked by khaleel87, 1 year ago

avail three resistors R1 R2 and R3 each of resistance 6 ohm be connected so that the combination has a strength of 9 Ohm​

Answers

Answered by Anonymous
3

Hey mate!!


Two resistance are connected in parallel


1/R = 1/6+1/6


R= 3Ω


Now, its connected with remaining one


R equivalent = 3Ω + 6Ω = 9Ω


Hope it helps!


#phoenix


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Answered by tipusultan93
1
Connect two 6 ohm resistors in parallel and then connect the resultant ressistance in series with a 6 ohm resistor.
Let me draw for you.


Thanks.
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