avail three resistors R1 R2 and R3 each of resistance 6 ohm be connected so that the combination has a strength of 9 Ohm
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Hey mate!!
Two resistance are connected in parallel
1/R = 1/6+1/6
R= 3Ω
Now, its connected with remaining one
R equivalent = 3Ω + 6Ω = 9Ω
Hope it helps!
#phoenix
khaleel87:
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Answered by
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Connect two 6 ohm resistors in parallel and then connect the resultant ressistance in series with a 6 ohm resistor.
Let me draw for you.
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Let me draw for you.
Thanks.
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