꧁Avantika parmar꧂
third I'd owner
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Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and ∠ABC = 60°. Then construct a triangle whose sides are 34 of the corresponding sides of the triangle ABC.
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Constructing △ABC:
Step 1: Draw base BC of length 6 cm using a ruler.
Step 2: Draw a ray from point B at an angle of 60
∘
.
Step 3: Mark an arc of radius 5 cm on the ray is drawn from B and label the intersection point as A. Join A−C
△ABC is the given triangle.
Constructing △EBD with sides
4
3
times the sides of △ABC
Step 1: Draw a ray BX on the opposite side of A.
Step 2: Mark 4 equidistant points B
1
,B
2
,B
3
,B
4
on ray BX
Step 3: Join B
4
to point C.
Step 4: Draw B
3
D parallel to B
4
C and mark the intersection point with line BC as D.
Step 5: Draw DE parallel to CA and mark the intersection point with AB as E.
△EBD is the required triangle.
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