Math, asked by PragyaTbia, 1 year ago

अवयव पाडा: 5y² + 5y - 10

Answers

Answered by PrinceSubham
3
5y^2+5y -10
= 5y^2 + 10y-5y -10
= 5y(y-2) + 5 (y-2)
=(5y+5 ) (y-2)





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Answered by hukam0685
3
अवयव पाडा: 5y² + 5y - 10

5 {y}^{2}  + 5y - 10 \\  \\  = 5 {y}^{2}  + (10 - 5)y - 10 \\  \\  = 5 {y}^{2}  + 10y - 5y - 10 \\  \\ =  5y(y + 2) - 5(y + 2) \\  \\  = (5y - 5)(y + 2) \\  \\
5 {y}^{2}  + 5y - 10 = (5y - 5)(y + 2) \\  \\
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