Math, asked by PragyaTbia, 11 months ago

अवयव पाडा: x² - 10x + 9

Answers

Answered by anusha6350
2

x^2-10x+9

x^2-9x-x+9

x(x-9)-1(x-9)

(x-9)(x-1)

Answered by hukam0685
1
अवयव:

 {x}^{2}  - 10x + 9 \\  \\  {x}^{2}  - (9 + 1)x + 9 \\  \\  {x}^{2}  -9x - x + 9 \\  \\ x(x - 9) - 1(x - 9) \\  \\ (x - 9)(x - 1) \\  \\
 {x}^{2}  - 10x + 9 = (x - 9)(x - 1) \\  \\
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