Question

अवयव पाडा: x³ - 64y³

Answer 1

अवयव पाडा: x³ - 64y³

${a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} ) \\ \\ a = x \\ \\ b = 4y \\ \\ {x}^{3} - ( {4y)}^{3} = (x - 4y)( {x}^{2} + (x)(4y)+ {(4y)}^{2} ) \\ \\ = (x - 4y)( {x}^{2} + 4xy + 16 {y}^{2} )$

${x}^{3} - 64 {y}^{3} = (x - 4y)( {x}^{2} + 4xy + 16 {y}^{2} )$

Answer 2

Solution :

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We know the algebraic identity:

a³ - b³ = ( a - b )( a² + ab + b² )

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x³ - 64y³

= x³ - ( 4y )³

= ( x - 4y )[ x² + x•4y + (4y)² ]

= ( x - 4y )( x² + 4xy + 16y² )

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