Question

Average kinetic energy during its motion from the position of equilibrium to the end

Answer 1

Answer:

Explanation: this is not so exact dont be offended

For trying to find the answer I used integration to find the average value of the velocity as time dependent function

12mv2=12mA2ω2cos2ωt,

from 0 to π2ω, I am getting π2ma2ν2, which is correct.

However when using velocity as a function of position

12mv2=12mw2(A2−x2)

from 0 to A I am getting a different answer, 13π2ma2ν2.

Why is that the case? hope this helpful