average of 1st n natural numbers
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Answered by
0
n( n-1) that's your answer.
uneq95:
no problem
can u please answer 1 more quetion
range of 1st n natural numbers
remember natural nos start from 1 while whole nos start from 0. this guy told the avg of first while nos
please
ok range is difference of the largest number and the lowest
ok
so here largest is n ans smallest is 1
so range comes out tk be n-1
is it correct?
Answered by
2
The natural number start from 1.
The sum of first n natural numbers is. n(n+1)/2
the avg = {n(n+1)/2 }/n
= (n+1)/2
The sum of first n natural numbers is. n(n+1)/2
the avg = {n(n+1)/2 }/n
= (n+1)/2
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