average of 3 number is 7 and the average of 2 of them is 4 . then the 3rd number is
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x+y+z/2=7
and x+y/2=4.. so put this value 1st equation...
4+(z/2)=7
z/2=3..so z=6
and x+y/2=4.. so put this value 1st equation...
4+(z/2)=7
z/2=3..so z=6
rehan778866khap56hzs:
sorry in above ans. (x+y+z)/3 is there....
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Ans.
Let the numbers are a, b and c.
Then,
(a + b + c)/3 = 7
or, (a + b + c) = 21 .....(i)
(a + b)/2 = 4
or, (a + b) = 8 .....(ii)
Putting a+b=8 in (i), we get
8 + c = 21
i.e., c = 13.
Hence the third number is 13.
☆I HOPE THAT THIS HELPS YOU.☆
Let the numbers are a, b and c.
Then,
(a + b + c)/3 = 7
or, (a + b + c) = 21 .....(i)
(a + b)/2 = 4
or, (a + b) = 8 .....(ii)
Putting a+b=8 in (i), we get
8 + c = 21
i.e., c = 13.
Hence the third number is 13.
☆I HOPE THAT THIS HELPS YOU.☆
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