Question

Average of 3 numbers abc is given as 48. Average of a,b,c,d is 46. Its given that e is having 3 more than d, then average of b,c,d,e is 45. What is the score of a?

Answer 1

1. Step-by-step explanation:

a=47 i shared a picture above

Answer 2

Answer:

47

Step-by-step explanation:

Average of 3 numbers abc is given as 48

So, $48=\frac{a+b+c}{3}$

$48 \times 3=a+b+c$

$144=a+b+c$ ---A

Average of a,b,c,d is 46.

$46=\frac{a+b+c+d}{4}$

$46 \times 4=a+b+c+d$

$184=a+b+c+d$

Using A

$184=144+d$

$184-144=d$

$40=d$

e is having 3 more than d

So, e = d+3=40+3=43

average of b,c,d,e is 45

$45=\frac{b+c+d+e}{4}$

$45=\frac{b+c+40+43}{4}$

$45 \times 4=b+c+40+43$

$180=b+c+83$

$180-83=b+c$

$97=b+c$

Substitute the value in A

$144=a+97$

$144-97=a$

$47=a$

Hence the score of a is 47