Question

Average of 3 numbers abc is given as 48. Average of a,b,c,d is 46. Its given that e is having 3 more than d, then average of b,c,d,e is 45. What is the score of a? A) 46 b) 48 c) 49 d) 47

Answer 1

Answer:

a = 47

Step-by-step explanation:

(a+b+c)/3 =48

a+b+c =48 * 3  = 144   ........ (1)

(a+b+c+d)/4 = 46

a+b+c+d  = 46 * 4 = 184  .........  (2)

e=3+d

(b+c+d+e)/4 = 45

b+c+d+e =45 * 4 = 180

∴ b+c+d+(3+d) = 180

⇒ b+c+2d+3=180

⇒b+c+2d=177     ....... (3)

(2)  -  (1)  ⇒ d = 40

Put d=40 in (3) ⇒ b+c = 177 - 2* 40 =177- 80 =97

Put b+c = 97 in (1) ⇒ a+97=144 ⇒ a =144- 97 = 47