Question

Average of a, b, and c is 11; average of c, d and e is 17; average of e and f is 22 and average of e and c is 17. find out the average of a, b, c, d, e and f:

Answer 1

a+b+c=11×3=33-----(1)
c+d+e=17×3=51-----(2)
e+f=22×2=44--------(3)
c+e=17×2=34--------(4)
now(1)+(2)+(3)=
a+b+c+c+d+e+e+f=33+51+44
(a+b+c+d+e+f)+(c+e)=128
a+b+c+d+e+f=128-34 from(4)
a+b+c+d+e+f=94
average is
$\frac{a + b + c + d + e + f}{6} = \frac{94}{6}$
=15.667
hope it'll help
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